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calculate the length of a train ticket (part 1)<\/p>\n
of a train ticket (part 1) Help! am trying to make a video to explain the calculation of a train ticket length in seconds. but i dont understand what i am doing wrong to get the answer<\/p>\n
A:<\/p>\n
You have the order of operations the wrong way round. You shouldn’t use the ‘=’ sign to add two numbers. This would be the same as doing a = 5 + 6. This will give you the result of 7, which you have not supplied as an input. Instead, you need to use two separate expressions (like 5 + 6) and then run one through your transformations at the end.
\nHere is the equation you need to use for how long the journey will take:
\n= [Duration of first leg] + [Duration of second leg]<\/p>\n
To do this, we can make a couple of assumptions. First, if the train going to Manchester takes twice as long as the train going to London, then we could say
\n= (1 hour in train going to Manchester) + (4 hour in train going to London)<\/p>\n
If we now assume that your legs are quite long, then we can replace the values for the duration of the train journey. So we need to look at the durations of the individual legs.<\/p>\n
It is made up of two segments, one from London to Manchester and the other from London to Crewe. So we could say that the first leg is 2.5 hours, and the second leg is 3 hours. We could then calculate this as follows:
\n= 2.5 + 3<\/p>\n
We can use this later to represent the time the journey takes.
\nOne last thing to say is that the order of operations has changed slightly here.
\nLet’s say you were calculating the time of a flight. You would say:
\n= [distance in miles] \/ [time to travel]<\/p>\n
You would then go and find out the time to travel, which would be ‘1 hour’. You then multiply the two together and divide by 3600 to work out the time in hours.<\/p>\n
Q:<\/p>\n
Difference between setThreadExecutionCount() and threadCount() in java<\/p>\n
What is difference between below two methods in java?
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\n private static final int THREAD_COUNT =<\/p>\n
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