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Your DVD is in Region 2 which is a lot more complex than just setting Region Code 0, in most cases and there isn’t a simple way to know what you should change the Region Code to, to get your DVD to play on a Region Free DVD player. The easiest thing to do is to just rip the DVD to hard disk and then either edit the Region Code out of the MP4 header or disable the region code detection all together (that may require converting using Handbrake). If you’re doing this for viewing on a region free DVD player though you’ll most likely end up with a region free DVD that won’t play on a region free DVD player.<\/p>\n
Q:<\/p>\n
Showing that $d$ and $d^n$ are equivalent when we have an automorphism of a free $\\mathbb{Z}$-module<\/p>\n
Let us consider the free $\\mathbb{Z}$-module $F_0$ generated by the indeterminate $x_0$ and $\\mathbb{Z}$ the ring of integers. Let $G\\le Aut(F_0)$ be a finite group of automorphisms of this $\\mathbb{Z}$-module. The quotient $\\mathbb{Z}[G]\\to A(G)\\le Aut_0(F_0)$ defined by the action of $G$ on $F_0$ is an epimorphism where we identify $\\mathbb{Z}[G]$ with the group ring $\\mathbb{Z}[G][F_0]$ and $A(G)$ with the automorphism group of the free $\\mathbb{Z}$-module $F_0$. In the ideal case, $A(G)$ is isomorphic to the elementary abelian group $A_n(\\mathbb{Z})$ of order $n!$.
\nFirst question. To define an action of $A(G)$ on $F_0$, it’s necessary that $G$ be a subgroup of $A(G)$. Is there an easy way to determine whether $G$ is a subgroup of $A(G)$? In the ideal case $G\\le A(G)$.
\nLet us assume that $G$ is a subgroup of $A(G)$. Can I tell from the epimorphism $p: \\mathbb<\/p>\n
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