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\n$$e(n) = \\exp\\left(\\exp\\left(\\exp\\left(\\exp\\left(\\cdots\\right)\\right)\\right)\\right)$$
\nwhere the $n$th digit is the number of times the “trail” of brackets occurs. For $e(1) = 2.71828\\ldots$, we get $e(2) = 5.71515\\ldots$, $e(3) = 11.83459\\ldots$, etc. One can verify that $e(n)$ grows without bound by induction.
\nOf course this is impossible to compute exactly. But my main question is: Why is this sequence divergent?<\/p>\n
\n$$\\log e(n) = \\log\\exp\\left(\\exp\\left(\\exp\\left(\\exp\\left(\\cdots\\right)\\right)\\right)\\right) = \\log (1+1\/2+1\/4+\\ldots).$$
\nUsing the arithmetic-geometric mean inequality, we have
\n$$\\log e(n) \\ge \\log(n+1) > 1,$$
\nwhich of course means $e(n)$ is infinite.<\/p>\n