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A:
The answer that I get from the link that you sent is that the first filename is the code name for the missing file that is the one that you are trying to download in the second file.
If I understand you correctly, this is what you should do:
Download the first file, and rename it so that the code name is the one you are trying to download.
Download the second file and rename it so that it has the code name of the missing file.
Rename your complete file in step 1 so that it has the code name of the new file.
Let’s say your second file was named 14.rar, your complete file would then be 14-files.rar.
Your problem is with the the code name of the missing file. Since the first file has the code name that you are trying to obtain, you should rename the complete file to 14.rar in the next step so that you will have the code name that you are trying to obtain.
Also, remember to manually delete the.rar and.txt files that you downloaded in step 1. The reason for this is that those files are the ones that actually contain the code name of the missing file.
EDIT:
After taking a look at the linked website and understanding your problem a little better, I have decided that the approach I mentioned above will not work.
First, it says that the second file that you are trying to obtain contains two files (a.rar and a.txt). This means that you need to extract both of those two files from the.rar archive before you can extract the.txt file.
The way that I see it, is that you are trying to bypass this two step process by opening the.rar file and just extracting the.txt file directly, without extracting the other one.
You can’t do this, since the arccat gets you the code name of the whole archive, not just the parts that are inside of it. The.rar file will always have a code name in it, and that is not what you want.
Q:
Regex on list of values
I have a list of values
inputList=[“value1″,”value2″,”value3″,”value4″,”value5″,”value6”]
I want to group them by their first value and put the second into a new list so my output is
outputList=[“valuen1″,”value2”,”value
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